Energy Density in Magnetic Field

A long solenoid with 40 turns per cm carries a current of 1A. The magnetic energy stored per unit volume is _____$\raisebox{1ex}{$\mathrm{\pi } J$}\!\left/ \!\raisebox{-1ex}{$m^3$}\right.$
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By inserting a soft iron piece into a solenoid, strength of the magnetic field

A current of 2A flows through a solenoid of self-inductance of 3 mH. the energy stored in the solenoid will be-

A solenoid of inductance 2H carries a current of 1A. What is the magnetic energy stored in a solenoid?
 

The expression for the energy density in the magnetic field is given by,

$u=\frac{1}{2}\frac{B^2}{{\mu }_0}$

Where, the value of ${\mu }_0$ is $8.85\times {10}^{-12} \mathrm{F}/\mathrm{m}$.

The magnetic field stored per unit volume is $\mathrm{nBH} \mathrm{J}/{\mathrm{m}}^3$. Here the value of $n$ is ?

Write the energy density formula in the case of a magnetic field or inductor.

In an electromagnetic wave, the average energy density associated with the magnetic field will be

A coil has an inductance of $5 \mathrm{H}$ and a resistance $20 \mathrm{\Omega }$. An emf of $100 \mathrm{V}$ its applied to it. What is the energy stored (in joule) in the magnetic field, when the current has reached its final steady value?

Current flowing through a solenoid having inductance $2 \mathrm{mH}$ is $4 \mathrm{A}$. Find the energy stored in the solenoid.

Magnetic energy stored in the solenoid in the terms of magnetic field $B$, area $A$ and length $L$ of the solenoid.

Cotyledons are also called-